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On 26 Nov 2007, at 17:18, Ian Potter wrote:
I don't know if this was an issue with the original command or not, but try this: $obj = new Object(); $obj = new Object();
I don't know if this was an issue with the original command or not, but try this:
$obj = new Object(); $obj = new Object();
Ooops, sorry, I forgot to escape '$'.
This should work.
--Hans
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