[TxMt] Re: How can I find and replace carriage returns?

[Carpii UK]

>
>
> Can you please help me understand what is happening between these two
> expressions?
>
> ^   beginning of the line
>
> .*::.*
>
>
> $  end of the line
>



^   match the beginning of the line

.* followed by 0 or more characters (apart from newline)

:: followed by 2 literal colon characters

.* followed by 0 or more characters (apart from newline)

$  followed by the end of the line (a \n character)


also…
>
> can you please tell me what the zero after the $ doing in this string?
>
> getValue( $0; 1) ;
>
>

The $0 is a way of referencing one of the captures the regular expression
made
I'm not entirely sure this capturing syntax is right, normally I use
brackets to capture, yet it seems to work in textmate.

We need to do this otherwise we don't know what to output after getValue(





>
>
>
> On Feb 7, 2016, at 7:29 AM, Carpii UK <carpii.uk at gmail.com> wrote:
>
> Try using a regular expression like this..
>
> http://carpii.homeip.net/skitch/Find-20160207-132857.png
>
> The expression is ^.*::.*$
>
>
>
>
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